Circuit 3 of 48: The Voltage Divider

By: Dominic Sciarrino | Stompbox Electronics | Last Updated: February 26th, 2026

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You’ve plugged a 9V power supply into a guitar pedal. But the circuit inside isn’t running 9 volts everywhere. Different stages need different voltages to operate correctly. A transistor amplifier stage needs a specific bias point. An op-amp needs a reference to work from. Where do those voltages come from?

The answer, in most single-supply guitar pedal circuits, is the voltage divider. It is two resistors and nothing else, yet it appears in virtually every analog pedal ever designed. Understanding it is non-negotiable if you want to understand how pedal circuits work.

This post also introduces the potentiometer as a variable voltage divider, which is the foundation of every volume control and most tone controls you’ll ever wire up.

Your guitar produces a continuously varying voltage that swings above and below zero volts. The positive peaks go above ground; the negative troughs dip below it. On an oscilloscope, it looks like a wave oscillating around the 0V line. In other words, your guitar signal is an AC signal.

Figure 3.1 A sine-wave simulating a guitar signal, centered at 0V.
Figure 3.1: A sine-wave simulating a guitar signal, centered at 0V.

This is perfectly normal. It’s how AC signals work. But it creates a problem when you try to process that signal inside a guitar pedal.

A typical guitar pedal runs on a single 9V supply. That supply provides voltages between 0V (ground) and +9V. It produces no negative voltages on its own*.

When you feed a guitar signal into a circuit powered this way, the negative half of the signal falls outside the range the circuit can handle. The transistors or op-amps in the circuit simply cannot process a voltage below their ground reference. That portion of the signal gets clipped off.

Figure 3.2 The guitar signal with negative values cut off, due to the allowable range of the effects circuit being 0 - 9V.
Figure 3.2: The guitar signal with negative values cut off, due to the operating range of the effects circuit being 0 – 9V.

The solution is to shift the entire waveform upward so that both the positive and negative swings stay within the circuit’s operating range. This process is called biasing.

Biasing superimposes the AC guitar signal on top of a fixed DC voltage. The AC component still swings the same amount above and below its center, except now that center is above zero, and the whole waveform lives in positive territory.

The standard approach for single-supply pedal circuits is to bias at half the supply voltage. On a 9V supply, that means generating a 4.5V DC reference. The signal swings equally above and below 4.5V, keeping the peaks below 9V and the troughs above 0V.

Figure 3.3 The guitar signal, biased to 4.5V, with the green line marking the bias point.
Figure 3.3: The guitar signal, biased to 4.5V, with the green line marking the bias point.

The circuit that generates the bias voltage is called a voltage divider. It consists of two resistors in series, connected between the supply voltage and ground. The output (the bias voltage) is taken from the junction between the two resistors.

Figure 3.4: The voltage divider circuit schematic.
Figure 3.4: The voltage divider circuit schematic.

The output voltage is determined by the ratio of R2 to the total resistance. The equation is:

Equation 3.1 The Voltage Divider equation.
Equation 3.1: The Voltage Divider equation.

In plain language: Vout is a fraction of Vin. That fraction equals R2 divided by the sum of both resistors. If R1 and R2 are equal, R2 is exactly half the total, so Vout is exactly half of Vin.

R1 = 10kΩ
R2 = 10kΩ
Vin = 9V

Vout = 9 x (10k / 20k)
Vout = 9 x 0.5
Vout = 4.5V ✓

Equal values → half the supply voltage

R1 = 20kΩ
R2 = 10kΩ
Vin = 9V

Vout = 9 x (10k / 30k)
Vout = 9 x 0.333
Vout = 3V ✓

R2 is 1/3 of total → 1/3 of supply

The resistor ratio is what sets Vout. Equal resistors give half the supply. A 2:1 ratio (R1:R2) gives one-third the supply. You can achieve any target voltage by choosing the right ratio.

For the standard 4.5V bias point on a 9V supply, any two equal-value resistors will work. Common choices are 10kΩ, 22kΩ, 47kΩ, or 100kΩ.

Here is something the equation alone doesn’t tell you. The actual resistor values determine how well the divider holds its output voltage when another circuit is connected to it.

When you connect the bias output to an effect circuit, that circuit has its own input impedance. To the voltage divider, the effect circuit “looks like” a resistor in parallel with R2. That parallel combination reduces the effective value of R2, which shifts Vout lower than you calculated.

This is called loading. The connected circuit is loading the voltage divider.

Figure 3.5: Adding a loading resistance to the voltage divider causes the voltage divider to "see" a lower value of R2, resulting in a lower output voltage.
Figure 3.5: Adding a loading resistance to the voltage divider causes the voltage divider to “see” a lower value of R2, resulting in a lower output voltage.

The way to minimize loading is to use smaller resistor values in the divider. A lower-value divider naturally draws more current from the supply and is less affected by the relatively higher impedance of the load. The load becomes a smaller fraction of the parallel combination.

But smaller resistors waste more current and can generate heat. There is a tradeoff.

The voltage divider doesn’t have to use two fixed resistors. If you replace the entire divider with a potentiometer then you have a variable voltage divider. Potentiometers (or “pots“) are essentially a resistor with a moveable wiper that allows you to tap off a variable resistance.

This is exactly how passive volume control works in guitars and guitar pedals.

The input signal enters at the top of the potentiometer. Ground is at the bottom. The wiper output goes to the next stage of the circuit. As you turn the pot clockwise:

  1. Wiper at bottom: full resistance above, zero below → The output is connected directly to ground, signal is silenced.
  2. Wiper at center: half the pot resistance above and below → The signal is attenuated to roughly half its normal amplitude.
  3. Wiper at top: full resistance below, zero above → full signal passes to the output through the wiper.
Figure 3.6: A volume control, built with a potentiometer acting as a variable AC signal voltage divider.
Figure 3.6: A volume control, built with a potentiometer acting as a variable AC signal voltage divider.

This same principal – a signal input at the top of a pot, ground at the bottom, output from the wiper – is the basis of almost every volume, gain, and level control you will encounter in guitar pedal design.

Build a voltage divider on the breadboard using two 10kΩ resistors. Connect the input to your 9V supply rail and ground at the bottom. Measure the output voltage with a multimeter. It should read approximately 4.5V.

Then, swap R1 for a 47kΩ resistor (keeping R2 at 10kΩ). Predict the new Vout using the equation before you measure. Then measure and compare.

With the 10kΩ / 47kΩ divider built, place a 10kΩ resistor in parallel with R2 (from the Vout node to ground). This simulates a circuit with a 10kΩ input impedance connected to your bias point. Measure Vout again.

  1. Compare to the unloaded value.
  2. Compare to the theoretical prediction using the equation with the parallel combination as the effective R2.

Wire a 100kΩ potentiometer as a voltage divider with your guitar signal at the top terminal and ground at the bottom terminal. Take the output from the wiper. Connect the wiper to an amplifier. Sweep the pot and observe the signal level changing.

Figure 3.7: Potentiometer hooked up as a variable voltage divider, except instead of dividing a DC voltage, this one divides an AC signal (your guitar signal). This is also called a passive volume control.
Figure 3.7: Potentiometer hooked up as a variable voltage divider, except instead of dividing a DC voltage, this one divides an AC signal (your guitar signal). This is also called a passive volume control.
PartQuantity
10kΩ Resistor2
47kΩ Resistor2
100kΩ Potentiometer (linear taper)1
Breadboard (or PROTIS 1 board)1
Multimeter1

The PROTIS 1 Development Board includes a built-in reference voltage generator circuit – a voltage divider with selectable output. The reference select header on the right side of the board offers three options via a jumper:

  • 4.5V – use when the circuit is powered by 9V (standard)
  • 6V – use when the circuit is powered by 12V
  • 9V – use when the circuit is powered by 18V

Access the reference output via the REFERENCE header along the right side of the prototyping area using a male-to-male jumper wire. Connect this to any node in your breadboarded circuit that requires a bias voltage.

The Reference Voltage Generator on the PROTIS 1 Guitar Effects Development Board.
Figure 3.8: The Reference Voltage Generator on the PROTIS 1 Guitar Effects Development Board.

[1] Stompbox Electronics Voltage Divider Calculator
[2] R.G. Keen – Bias Network Resistor Selection (Geofex)
[3] Iota Pedals – Voltage Divider Basics


Guitar Effects Design in 48 Circuits or Less

This post is part of the 48 Circuits or Less series by Stompbox Electronics. Each installment covers one fundamental pedal circuit building block – concept, demonstration, and supplemental resources.

View more articles in this series here.

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